y=y^2/5

Solution for y=y^2/5 equation:

y=y^2/5

We move all terms to the left:

y-(y^2/5)=0

We get rid of parentheses

-y^2/5+y=0

We multiply all the terms by the denominator


-y^2+y*5=0

We add all the numbers together, and all the variables

-1y^2+y*5=0

Wy multiply elements

-1y^2+5y=0

a = -1; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·(-1)·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*-1}=\frac{-10}{-2}
=+5
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*-1}=\frac{0}{-2}
=0
$